php get date from date

20.07.202220.07.2022 admin 0 Comments

How to get only the date from a DateTime object?

I have a variable of type DateTime() and I want to get only the date of it to compare it with an other date variable. Here is how I tried to do that, but I get extra data that I don’t need:

var_dump($date) returns : object(DateTime)#617 (3) < ["date"]=>string(19) «2017-04-09 00:00:00» [«timezone_type»]=> int(3) [«timezone»]=> string(12) «Africa/Tunis» > So I want to get something like this : 09/04/2017

UPDATE: This is my action code (I have a form in twig that contains a date type input) :

3 Answers 3

You were doing it (almost right). For reference here a copy-paste your code:

The last line returns the desired string. If you want to output that you can just echo it:

Returns date formatted according to given format

It says «returns» with which means returned to the context of the call: the expression of the call ‘is substituted’ by the returned value. If it would output it in the function, then the manual would have said something like «prints» or «outputs» or «dumps». You can read more about what ‘returning a value’ means in this part of the manual. The first example shows the exact equivalent of what you tried to do:

Lastly, with regards to the use of var_dump : please note that this is intended for debugging purposes and normally not for displaying output to the user. var_dump will normally just dump «All public, private and protected properties of objects» of the given object. You should check the var_dump manual pages it contains many examples.

Источник

Php get date from date

(PHP 4, PHP 5, PHP 7, PHP 8)

date — Форматирует вывод системной даты/времени

Описание

Список параметров

Возвращаемые значения

Ошибки

Список изменений

Версия	Описание
8.0.0	timestamp теперь допускает значение null.

Примеры

Пример #1 Примеры использования функции date()

// установка часового пояса по умолчанию.
date_default_timezone_set ( ‘UTC’ );

// выведет примерно следующее: Monday
echo date ( «l» );

// выведет примерно следующее: Monday 8th of August 2005 03:12:46 PM
echo date ( ‘l jS \of F Y h:i:s A’ );

/* пример использования константы в качестве форматирующего параметра */
// выведет примерно следующее: Mon, 15 Aug 2005 15:12:46 UTC
echo date ( DATE_RFC822 );

Чтобы запретить распознавание символа как форматирующего, следует экранировать его с помощью обратного слеша. Если экранированный символ также является форматирующей последовательностью, то следует экранировать его повторно.

Пример #2 Экранирование символов в функции date()

Пример #3 Пример совместного использования функций date() и mktime()

Данный способ более надёжен, чем простое вычитание и прибавление секунд к метке времени, поскольку позволяет при необходимости гибко осуществить переход на летнее/зимнее время.

Пример #4 Форматирование с использованием date()

// Предположим, что текущей датой является 10 марта 2001, 5:16:18 вечера,
// и мы находимся в часовом поясе Mountain Standard Time (MST)

$today = date ( «F j, Y, g:i a» ); // March 10, 2001, 5:16 pm
$today = date ( «m.d.y» ); // 03.10.01
$today = date ( «j, n, Y» ); // 10, 3, 2001
$today = date ( «Ymd» ); // 20010310
$today = date ( ‘h-i-s, j-m-y, it is w Day’ ); // 05-16-18, 10-03-01, 1631 1618 6 Satpm01
$today = date ( ‘\i\t \i\s \t\h\e jS \d\a\y.’ ); // it is the 10th day.
$today = date ( «D M j G:i:s T Y» ); // Sat Mar 10 17:16:18 MST 2001
$today = date ( ‘H:m:s \m \i\s\ \m\o\n\t\h’ ); // 17:03:18 m is month
$today = date ( «H:i:s» ); // 17:16:18
$today = date ( «Y-m-d H:i:s» ); // 2001-03-10 17:16:18 (формат MySQL DATETIME)
?>

Примечания

Смотрите также

User Contributed Notes 20 notes

Things to be aware of when using week numbers with years.

Conclusion:
if using ‘W’ for the week number use ‘o’ for the year.

In order to define leap year you must considre not only that year can be divide by 4!

The correct alghoritm is:

if (year is not divisible by 4) then (it is a common year)
else if (year is not divisible by 100) then (it is a leap year)
else if (year is not divisible by 400) then (it is a common year)
else (it is a leap year)

So the code should look like this:

For Microseconds, we can get by following:

echo date(‘Ymd His’.substr((string)microtime(), 1, 8).’ e’);

FYI: there’s a list of constants with predefined formats on the DateTime object, for example instead of outputting ISO 8601 dates with:

echo date ( ‘Y-m-d\TH:i:sO’ );
?>

You can use

echo date ( DateTime :: ISO8601 );
?>

instead, which is much easier to read.

this how you make an HTML5 tag correctly

It’s common for us to overthink the complexity of date/time calculations and underthink the power and flexibility of PHP’s built-in functions. Consider http://php.net/manual/en/function.date.php#108613

date() will format a time-zone agnostic timestamp according to the default timezone set with date_default_timezone_set(. ). Local time. If you want to output as UTC time use:

$tz = date_default_timezone_get ();
date_default_timezone_set ( ‘UTC’ );

For HTML5 datetime-local HTML input controls (http://www.w3.org/TR/html-markup/input.datetime-local.html) use format example: 1996-12-19T16:39:57

To generate this, escape the ‘T’, as shown below:

If timestamp is a string, date converts it to an integer in a possibly unexpected way:

The example below formats today’s date in three different ways:

The following function will return the date (on the Gregorian calendar) for Orthodox Easter (Pascha). Note that incorrect results will be returned for years less than 1601 or greater than 2399. This is because the Julian calendar (from which the Easter date is calculated) deviates from the Gregorian by one day for each century-year that is NOT a leap-year, i.e. the century is divisible by 4 but not by 10. (In the old Julian reckoning, EVERY 4th year was a leap-year.)

This algorithm was first proposed by the mathematician/physicist Gauss. Its complexity derives from the fact that the calculation is based on a combination of solar and lunar calendars.

At least in PHP 5.5.38 date(‘j.n.Y’, 2222222222) gives a result of 2.6.2040.

So date is not longer limited to the minimum and maximum values for a 32-bit signed integer as timestamp.

Prior to PHP 5.6.23, Relative Formats for the start of the week aligned with PHP’s (0=Sunday,6=Saturday). Since 5.6.23, Relative Formats for the start of the week align with ISO-8601 (1=Monday,7=Sunday). (http://php.net/manual/en/datetime.formats.relative.php)

This can produce different, and seemingly incorrect, results depending on your PHP version and your choice of ‘w’ or ‘N’ for the Numeric representation of the day of the week:

Prior to PHP 5.6.23, this results in:

Today is Sun 2 Oct 2016, day 0 of this week. Day 1 of next week is 10 Oct 2016
Today is Sun 2 Oct 2016, day 7 of this week. Day 1 of next week is 10 Oct 2016

Since PHP 5.6.23, this results in:

Today is Sun 2 Oct 2016, day 0 of this week. Day 1 of next week is 03 Oct 2016
Today is Sun 2 Oct 2016, day 7 of this week. Day 1 of next week is 03 Oct 2016

I’ve tested it pretty strenuously but date arithmetic is complicated and there’s always the possibility I missed something, so please feel free to check my math.

The function could certainly be made much more powerful, to allow you to set different days to be ignored (e.g. «skip all Fridays and Saturdays but include Sundays») or to set up dates that should always be skipped (e.g. «skip July 4th in any year, skip the first Monday in September in any year»). But that’s a project for another time.

$start = strtotime ( «1 January 2010» );
$end = strtotime ( «13 December 2010» );

// Add as many holidays as desired.
$holidays = array();
$holidays [] = «4 July 2010» ; // Falls on a Sunday; doesn’t affect count
$holidays [] = «6 September 2010» ; // Falls on a Monday; reduces count by one

Or, if you just want to know how many work days there are in any given year, here’s a quick function for that one:

Источник

Get the year from specified date php

10 Answers 10

The DateTime class does not use an unix timestamp internally, so it han handle dates before 1970 or after 2038.

You can use the strtotime and date functions like this:

Note however that PHP can handle year upto 2038

If your date is always in that format, you can also get the year like this:

It appears the date is coming from a source where it is always the same, much quicker this way using explode.

You can achieve your goal by using php date() & explode() functions:

That is it. Happy coding 🙂

You can try strtotime() and date() functions for output in minimum code and using standard way.

You can use explode also

You wrote that format can change from YYYY-mm-dd to dd-mm-YYYY you can try to find year there

Not the answer you’re looking for? Browse other questions tagged php date or ask your own question.

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How to get time and date from datetime stamp in PHP?

How to achieve that? Can you give me example?

7 Answers 7

edit: To keep the AM/PM format use

strtotime creates a UNIX timestamp from the string you pass to it.

For more information about date() function, plz visit http://php.net/manual/en/function.date.php

This is probably not the cleanest way of doing it, but you can use an explode (note that there is NO validation at all here). It will be faster than a proper date manipulation.

If your version of PHP is new enough, check out date_parse() and the array it returns. You can then format date or time portions using the relevant entries.

This should do the trick:

You could also do something like this but it’s not preferred way:

Yes this is possible, and the perfect example can be found here http://php.net/manual/en/function.date.php

Not the answer you’re looking for? Browse other questions tagged php date or ask your own question.

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Date/Time Functions

User Contributed Notes 25 notes

I ran into an issue using a function that loops through an array of dates where the keys to the array are the Unix timestamp for midnight for each date. The loop starts at the first timestamp, then incremented by adding 86400 seconds (ie. 60 x 60 x 24). However, Daylight Saving Time threw off the accuracy of this loop, since certain days have a duration other than 86400 seconds. I worked around it by adding a couple of lines to force the timestamp to midnight at each interval.

When debugging code that stores date/time values in a database, you may find yourself wanting to know the date/time that corresponds to a given unix timestamp, or the timestamp for a given date & time.

The following script will do the conversion either way. If you give it a numeric timestamp, it will display the corresponding date and time. If you give it a date and time (in almost any standard format), it will display the timestamp.

All conversions are done for your locale/time zone.

For those who are using pre MYSQL 4.1.1, you can use:

TO_DAYS([Date Value 1])-TO_DAYS([Date Value 2])

For the same result as:

DATEDIFF([Date Value 1],[Date Value 2])

This dateDiff() function can take in just about any timestamp, including UNIX timestamps and anything that is accepted by strtotime(). It returns an array with the ability to split the result a couple different ways. I built this function to suffice any datediff needs I had. Hope it helps others too.

I needed a function that determined the last Sunday of the month. Since it’s made for the website’s «next meeting» announcement, it goes based on the system clock; also, if today is between Sunday and the end of the month, it figures out the last Sunday of *next* month. lastsunday() takes no arguments and returns the date as a string in the form «January 26, 2003». I could probably have streamlined this quite a bit, but at least it’s transparent code. =)

/* The two functions calculate when the next meeting will
be, based on the assumption that the meeting will be on
the last Sunday of the month. */

I wanted to find all records in my database which match the current week (for a call-back function). I made up this function to find the start and end of the current week :

Not really elegant, but tells you, if your installed timezonedb is the most recent:

Someone may find this info of some use:

Rules for calculating a leap year:

1) If the year divides by 4, it is a leap year (1988, 1992, 1996 are leap years)
2) Unless it divides by 100, in which case it isn’t (1900 divides by 4, but was not a leap year)
3) Unless it divides by 400, in which case it is actually a leap year afterall (So 2000 was a leap year).

In practical terms, to work out the number of days in X years, multiply X by 365.2425, rounding DOWN to the last whole number, should give you the number of days.

The result will never be more than one whole day inaccurate, as opposed to multiplying by 365, which, over more years, will create a larger and larger deficit.

I needed to calculate the week number from a given date and vice versa, where the week starts with a Monday and the first week of a year may begin the year before, if the year begins in the middle of the week (Tue-Sun). This is the way weekly magazines calculate their issue numbers.

Here are two functions that do exactly that:

Hope somebody finds this useful.

Use the mySQL UNIX_TIMESTAMP() function in your SQL definition string. i.e.

$sql= «SELECT field1, field2, UNIX_TIMESTAMP(field3) as your_date
FROM your_table
WHERE field1 = ‘$value'»;

The query will return a temp table with coulms «field1» «Field2» «your_date»

The «your_date» will be formatted in a UNIX TIMESTAMP! Now you can use the PHP date() function to spew out nice date formats.

Hope this helps someone out there!

//function like dateDiff Microsoft
//not error in year Bissesto

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php get date from date

How to get only the date from a DateTime object?

3 Answers 3