ora 00972 identifier is too long как исправить
Ora 00972 identifier is too long как исправить
SQL> select * from wms.v_upload_inc_doc_res_header ;
select * from wms.v_upload_inc_doc_res_header
*
ERROR at line 1:
ORA-00972: identifier is too long
SQL> drop view v_upload_inc_doc_res_header ;
SQL> CREATE OR REPLACE VIEW v_upload_inc_doc_res_header
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;
21 rows selected.
SQL> select * from NLS_SESSION_PARAMETERS ;
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SY Member ������: Middlebury, CT USA | Any chance some of v_upload_inc_doc_res_header characters are in russian? Keep in mind, identifier length is 30 bytes, not characters. SY. |
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Apex Member ������: Middlebury, CT USA | Check lengthb(‘v_upload_inc_doc_res_header’). SY. |
14 ��� 07, 17:39����[4524797] �������� | ���������� �������� ���������� |
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juks@gala.net Member ������: |
SQL> select length(‘V_UPLOAD_INC_DOC_RES_DETAIL’), lengthb(‘V_UPLOAD_INC_DOC_RES_DETAIL’), lengthc(‘V_UPLOAD_INC_DOC_RES_DETAIL’), length2(‘V_UPLOAD_INC_DOC_RES_DETAIL’), length4(‘V_UPLOAD_INC_DOC_RES_DETAIL’) from dual ; SQL> select * from v_upload_inc_doc_res_header2 ; Ошибка при выборке ORA-00972: слишком длинный идентификаторПомощь в написании контрольных, курсовых и дипломных работ здесь. Ошибка ORA-00904 «Недопустимый идентификатор Export to word Слишком длинный строковый параметр Слишком длинный строковой параметр. Что делать? ORA-00972 Cause: An identifier with more than 30 characters was specified. Action: Specify at most 30 characters. В отладочный файл, например. Просто текст, который передается на исполнение. Добавлено через 3 минуты эту ошибку получал в простом апдейте, когда проверял сам запрос. а так дело было в java бине не совсем правильно написал этот бин как только там исправил все исчезло. Добавлено через 20 секунд Помощь в написании контрольных, курсовых и дипломных работ здесь. Пишу программу на i8080 не идет код слишком длинный Ora-12154 TNS невозможно заданный идентификатор соединения ORA-00972: identifier is too longAll names of table are below 30 s select insert into «C_0SWMET_ResultsMonitoring*» ODI-1227: Task SrcSet0 (Loading) fails on the source ORACLE connection RAP_UE_SRC. at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:462) AnswersHi, Couple of things to try : Can you put a view on top of the source table and alias the columns to have a shorter name? pleaase check data type and column size in both source and target tables, and again reverse engineer you source and target table. Once it is done in model, open your interface and while mapping to target columns, please apply trim function. Hope this may helps you additoional fragment of log Internal GLOBAL jar:file:/C:/oracle/product/ODI_11.1.1g/oracledi/client/jdev/extensions/oracle.odi.navigator.jar!/com/sunopsis/graphical/gif/state/f_error.gif 2014-09-30 09:16:31.0 2014-09-30 09:16:31.0 0 972 ODI-1226: Step SWMET_ResultsMonitoring* fails after 1 attempt(s). ODI-1240: Flow SWMET_ResultsMonitoring* fails while performing a Loading operation. This flow loads target table SWMET_ResultsMonitoring*. ODI-1227: Task SrcSet0 (Loading) fails on the source ORACLE connection RAP_UE_SRC. Name Length I try 25-35 The name of the table in the From clause is fine, its columns like this : causing the ORA-00972 The pictures you have posted up dont tell me anything, and the error from the log doesnt give me the SQL its generated, please provide this so we can help you. ORA-00972: Identifier is too longI have a query that I am executing in visual studio’s query tool and I am getting the following error. ORA-00972: identifier too long. Now I believe I am aware that oracle has a 30 byte limit, but this is the query I am trying to execute. Unfortunately I will not be able to change the database structure itself as it is managed by another company that knows nothing about database normalization or is in a situation where they simply cannot or should not. I don’t know. Do take into account that «cef_v_cw_shipment» is a view. truck = ‘104490’ is just a sample integer for testing purposes. I have attempted various solutions but the right method (or looking for the right method) seems to elude me. P.S. Sorry if this is a dumb question. «rideNumber» is now an invalid identifier, I will return to this shortly. I think I’m aliasing it the wrong way but I’m not sure. Goign to find out. I am going with this syntax now as it is alot cleaner and easier to understand than the previous one. However I am still encountering ORA-00904: «rideNumber»: invalid identifier (this likely counts for shipmentNumber aswell in the join line. Trying to figure this one out still, google returns naming tips: no success. Still searching. Now following suggestions, this is the current syntax. It currently returns the error message: ERROR ORA-00904: «CS».»SHIPMENTNUMBER»: invalid identifier I am sorry, I did not design this database> ): hibernate oracle identifier is too long ORA-00972Im stuck with this problem. The database schema is provided by someone else so I cant simply change names. I tried add everywhere proper annotations, maybe I’m missing something (obvious)? Here is my full mapping (quite many classess), I’ll ommit getter/setters. The problem is when hibernate is trying to get all List controlRuleAttribs Controle Rule ControlRuleAttrib ControleRuleAttribType ControleRuleType EDIT Here is stacktrace: As you’ll find out, it fails here:
every object which mapping I added, has toString() method declared like this: And hibernate request: EDIT 2 Well after reading @Jens answer, I did some changes in the code. First I did as you wrote and it gave error:
I guess this is right, as I have composite primary key. Then I tried it this way: Quite close but it gives me the following exception:
So finally I removed And everything compiled except that when I try to reach collection, Hibernate is doing following query: Is there anyway I can make it work? :/ 3 Answers 3After struggling with this for last few hours I finally make it working within my project. The thing I did was this: ControlRule Basically pointing that the collection should use controlRuleId from composite primary key. So far its working great! The problem is the column Which is so long it can’t possibly exist in your database. I don’t see in the question any hint how it is actually named, but I am assuming the proper name is So the question is: Why is hibernate trying to access this column. The table it is in is a mapping table which is mapped in hibernate as: If you look at the @JoinTable annotation you’ll notice that it defines the table name as it is used and a join column. But a mapping table has two sets of join columns. The second on is not specified. Therefore the NamingStrategy you configured or if you didn’t configured any the default is used. Just specify the other set of join columns using the attribute inverseJoinColumns and all should be fine. The complete annotation should look like: Note: I have no idea if you need any of the nullable, updatable stuff on that column as well.
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