php get current year

Get the year from specified date php

10 Answers 10

The DateTime class does not use an unix timestamp internally, so it han handle dates before 1970 or after 2038.

You can use the strtotime and date functions like this:

Note however that PHP can handle year upto 2038

If your date is always in that format, you can also get the year like this:

It appears the date is coming from a source where it is always the same, much quicker this way using explode.

You can achieve your goal by using php date() & explode() functions:

That is it. Happy coding 🙂

You can try strtotime() and date() functions for output in minimum code and using standard way.

You can use explode also

You wrote that format can change from YYYY-mm-dd to dd-mm-YYYY you can try to find year there

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Источник

Php get current year

(PHP 4, PHP 5, PHP 7, PHP 8)

date — Форматирует вывод системной даты/времени

Описание

Список параметров

Возвращаемые значения

Ошибки

Список изменений

Примеры

Пример #1 Примеры использования функции date()

// установка часового пояса по умолчанию.
date_default_timezone_set ( ‘UTC’ );

// выведет примерно следующее: Monday
echo date ( «l» );

// выведет примерно следующее: Monday 8th of August 2005 03:12:46 PM
echo date ( ‘l jS \of F Y h:i:s A’ );

/* пример использования константы в качестве форматирующего параметра */
// выведет примерно следующее: Mon, 15 Aug 2005 15:12:46 UTC
echo date ( DATE_RFC822 );

Чтобы запретить распознавание символа как форматирующего, следует экранировать его с помощью обратного слеша. Если экранированный символ также является форматирующей последовательностью, то следует экранировать его повторно.

Пример #2 Экранирование символов в функции date()

Пример #3 Пример совместного использования функций date() и mktime()

Данный способ более надёжен, чем простое вычитание и прибавление секунд к метке времени, поскольку позволяет при необходимости гибко осуществить переход на летнее/зимнее время.

Пример #4 Форматирование с использованием date()

// Предположим, что текущей датой является 10 марта 2001, 5:16:18 вечера,
// и мы находимся в часовом поясе Mountain Standard Time (MST)

$today = date ( «F j, Y, g:i a» ); // March 10, 2001, 5:16 pm
$today = date ( «m.d.y» ); // 03.10.01
$today = date ( «j, n, Y» ); // 10, 3, 2001
$today = date ( «Ymd» ); // 20010310
$today = date ( ‘h-i-s, j-m-y, it is w Day’ ); // 05-16-18, 10-03-01, 1631 1618 6 Satpm01
$today = date ( ‘\i\t \i\s \t\h\e jS \d\a\y.’ ); // it is the 10th day.
$today = date ( «D M j G:i:s T Y» ); // Sat Mar 10 17:16:18 MST 2001
$today = date ( ‘H:m:s \m \i\s\ \m\o\n\t\h’ ); // 17:03:18 m is month
$today = date ( «H:i:s» ); // 17:16:18
$today = date ( «Y-m-d H:i:s» ); // 2001-03-10 17:16:18 (формат MySQL DATETIME)
?>

Примечания

Смотрите также

User Contributed Notes 20 notes

Things to be aware of when using week numbers with years.

Conclusion:
if using ‘W’ for the week number use ‘o’ for the year.

In order to define leap year you must considre not only that year can be divide by 4!

The correct alghoritm is:

if (year is not divisible by 4) then (it is a common year)
else if (year is not divisible by 100) then (it is a leap year)
else if (year is not divisible by 400) then (it is a common year)
else (it is a leap year)

So the code should look like this:

For Microseconds, we can get by following:

echo date(‘Ymd His’.substr((string)microtime(), 1, 8).’ e’);

FYI: there’s a list of constants with predefined formats on the DateTime object, for example instead of outputting ISO 8601 dates with:

echo date ( ‘Y-m-d\TH:i:sO’ );
?>

You can use

echo date ( DateTime :: ISO8601 );
?>

instead, which is much easier to read.

this how you make an HTML5 tag correctly

It’s common for us to overthink the complexity of date/time calculations and underthink the power and flexibility of PHP’s built-in functions. Consider http://php.net/manual/en/function.date.php#108613

date() will format a time-zone agnostic timestamp according to the default timezone set with date_default_timezone_set(. ). Local time. If you want to output as UTC time use:

$tz = date_default_timezone_get ();
date_default_timezone_set ( ‘UTC’ );

For HTML5 datetime-local HTML input controls (http://www.w3.org/TR/html-markup/input.datetime-local.html) use format example: 1996-12-19T16:39:57

To generate this, escape the ‘T’, as shown below:

If timestamp is a string, date converts it to an integer in a possibly unexpected way:

The example below formats today’s date in three different ways:

The following function will return the date (on the Gregorian calendar) for Orthodox Easter (Pascha). Note that incorrect results will be returned for years less than 1601 or greater than 2399. This is because the Julian calendar (from which the Easter date is calculated) deviates from the Gregorian by one day for each century-year that is NOT a leap-year, i.e. the century is divisible by 4 but not by 10. (In the old Julian reckoning, EVERY 4th year was a leap-year.)

This algorithm was first proposed by the mathematician/physicist Gauss. Its complexity derives from the fact that the calculation is based on a combination of solar and lunar calendars.

At least in PHP 5.5.38 date(‘j.n.Y’, 2222222222) gives a result of 2.6.2040.

So date is not longer limited to the minimum and maximum values for a 32-bit signed integer as timestamp.

Prior to PHP 5.6.23, Relative Formats for the start of the week aligned with PHP’s (0=Sunday,6=Saturday). Since 5.6.23, Relative Formats for the start of the week align with ISO-8601 (1=Monday,7=Sunday). (http://php.net/manual/en/datetime.formats.relative.php)

This can produce different, and seemingly incorrect, results depending on your PHP version and your choice of ‘w’ or ‘N’ for the Numeric representation of the day of the week:

Prior to PHP 5.6.23, this results in:

Today is Sun 2 Oct 2016, day 0 of this week. Day 1 of next week is 10 Oct 2016
Today is Sun 2 Oct 2016, day 7 of this week. Day 1 of next week is 10 Oct 2016

Since PHP 5.6.23, this results in:

Today is Sun 2 Oct 2016, day 0 of this week. Day 1 of next week is 03 Oct 2016
Today is Sun 2 Oct 2016, day 7 of this week. Day 1 of next week is 03 Oct 2016

I’ve tested it pretty strenuously but date arithmetic is complicated and there’s always the possibility I missed something, so please feel free to check my math.

The function could certainly be made much more powerful, to allow you to set different days to be ignored (e.g. «skip all Fridays and Saturdays but include Sundays») or to set up dates that should always be skipped (e.g. «skip July 4th in any year, skip the first Monday in September in any year»). But that’s a project for another time.

$start = strtotime ( «1 January 2010» );
$end = strtotime ( «13 December 2010» );

// Add as many holidays as desired.
$holidays = array();
$holidays [] = «4 July 2010» ; // Falls on a Sunday; doesn’t affect count
$holidays [] = «6 September 2010» ; // Falls on a Monday; reduces count by one

?>

Or, if you just want to know how many work days there are in any given year, here’s a quick function for that one:

Источник

How do I use PHP to get the current year?

I want to put a copyright notice in the footer of a web site, but I think it’s incredibly tacky for the year to be outdated.

How would I make the year update automatically with PHP 4 or PHP 5?

31 Answers 31

You can use either date or strftime. In this case I’d say it doesn’t matter as a year is a year, no matter what (unless there’s a locale that formats the year differently?)

On a side note, when formatting dates in PHP it matters when you want to format your date in a different locale than your default. If so, you have to use setlocale and strftime. According to the php manual on date:

To format dates in other languages, you should use the setlocale() and strftime() functions instead of date().

From this point of view, I think it would be best to use strftime as much as possible, if you even have a remote possibility of having to localize your application. If that’s not an issue, pick the one you like best.

My super lazy version of showing a copyright line, that automatically stays updated:

This year (2008), it will say:

Next year, it will say:

and forever stay updated with the current year.

Or (PHP 5.3.0+) a compact way to do it using an anonymous function so you don’t have variables leaking out and don’t repeat code/constants:

With PHP heading in a more object-oriented direction, I’m surprised nobody here has referenced the built-in DateTime class:

or one-liner with class member access on instantiation (php>=5.4):

I love strftime. It’s a great function for grabbing/recombining chunks of dates/times.

Plus it respects locale settings which the date function doesn’t do.

This one gives you the local time:

And this one UTC:

below is a bit of explanation of what it does:

Y will gives you four digit (e.g. 1990) and y for two digit (e.g. 90)

For 4 digit representation:

2 digit representation:

echo date(‘Y’) gives you current year, and this will update automatically since date() give us the current date.

It takes the current date and then you provide a format to it

and the format is just going to be Y. Capital Y is going to be a four digit year.

This code should do

And ‘echo’ this value.

If your server supports Short Tags, or you use PHP 5.4, you can use:

BTW. there are a few proper ways how to display site copyright. Some people have tendency to make things redundant i.e.: Copyright © have both the same meaning. The important copyright parts are:

Or you can use it with one line

If you wanna increase or decrease the year another method; add modify line like below.

use a PHP date() function.

and the format is just going to be Y. Capital Y is going to be a four digit year.

Get full Year used:

Or get only two digit of year used like this:

My way to show the copyright, That keeps on updating automatically

It will output the results as

best shortcode for this section:

You can use this in footer sections to get dynamic copyright year

in my case the copyright notice in the footer of a wordpress web site needed updating.

thought simple, but involved a step or more thann anticipated.

Open footer.php in your theme’s folder.

Locate copyright text, expected this to be all hard coded but found:

Now we know the year is written somewhere in WordPress admin so locate that to delete the year written text. In WP-Admin, go to Options on the left main admin menu:

Then on next page go to the tab Disclaimers :

and near the top you will find Copyright year:

DELETE the © symbol + year + the empty space following the year, then save your page with Update button at top-right of page.

With text version of year now delete, we can go and add our year that updates automatically with PHP. Go back to chunk of code in STEP 2 found in footer.php and update that to this:

Done! Just need to test to ensure changes have taken effect as expected.

this might not be the same case for many, however we’ve come across this pattern among quite a number of our client sites and thought it would be best to document here.

Источник

How to Get Year From a Date in PHP?

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Problem:

You have a date which consists of day, month, and year. You just want to retrieve the year from that date.

Solution:

There are few ways you can retrieve year from a date. In the following you’ll see different ways to retrieve year from current date or from any date –

Method 1: Using only date() function to get current year

PHP’s date() function can let you know date and time related information based on the formatting string it takes in its first parameter. It can take two parameters. If you use only one parameter, It will return info about the current time.

Depending on the formatting parameter you can get two types of output as the year-

Now, see these in action in the example-

Output:
4 digit of current year is: 2014
2 digit of current year is: 14

Method 2: Using strtotime() and date() function to get year from any date

In this method, to get the year, we’ll follow two steps-

See how it works in action in the following example-

Output:
4 digit of current year is: 1993
2 digit of current year is: 93

Method 3: Using DateTime class to get current year

From PHP 5.2, PHP provides some ready-made classes to solve daily problems. One of the classes is DateTime which helps to solve date time related issues.

To get current year using DateTime class, we’ll follow two steps-

See the following example-

Output:
4 digit of current year is: 2014
2 digit of current year is: 14

Method 4: Using CreateFromFormat() method to get year from any date

In this method, we’ll retrieve year from any date in two steps-

See it in action in the following example –

Output:
4 digit of current year is: 1993
2 digit of current year is: 93

Источник

How to get the first day of the current year?

I need to use PHP DateTime to get the first day of the current year. I’ve tried:

But this seems to be returning the first day of the current month: 2014-09-01 09:28:56

Why? How do I correctly get the first day of the current year?

11 Answers 11

Your relative date format ‘first day of this year’ is correct by returning the first day of the month because of the definition of first day of :

Sets the day of the first of the current month. This phrase is best used together with a month name following it. (See PHP-doc)

To get the first day of the current year with the relative format you can use something like this:

Or use only text in the strtotime function:

You can get the current date and then set day and month to 1:

Optionally, you can set the time to midnight:

If you want to get first day of current year just use this code

Just wanted to record some nuance with the answer by lorem monkey

The suggested method might cause issues with when using time zones.

scenario: consider current system time is 2018-01-01 00:20:00 UTC and system default time zone is set to UTC.

date(‘Y’) will give you 2018

if you are doing something like:

This will compute to ‘first day of january 2018’ but you actually needed the first date of your current year in America/New_York, which is still 2017.

Stop dropping the ball man, its not new year yet!

So it is better to just do

And then do the modifications as needed by using the DateTime::modify() function.

Relative date formats are fun.

My scenario: I wanted to get the bounds of this year as in 2018-01-01 00:00:00 to 2018-12-31 23:59:59

This can be achieved in two ways with relative date formats.

one way is to use the DateTime::modify() function on the object.

Another way to do this is to separate the relative strings with a comma like so:

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